Question

net capacitance of three identical capacitors in series is 3uf what will be their net capacitance if connected in parallel​

Answer 1

Answer:

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Explanation:

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Answer 2

Let the capacitance of three identical

capacitors= C

Since they were in Series capacitance is given

by -

$C_{net}= \frac{1}{C_1} +\frac{1}{C_2}+ \frac{1}{C_3}$

In our Case,

$3= \frac{1}{C} +\frac{1}{C}+ \frac{1}{C}$

$\implies\frac{1}{C} +\frac{1}{C}+ \frac{1}{C}=3$

$\implies\frac{1+1+1}{C}=3$

$\implies\frac{3}{C}=3$

$\implies C=3$

In parallel,

$C_{net}=C_1 + C_2 + C_3$

$C_{net}=C+ C + C$

$C_{net}=3C$

$C_{net}=3×3$ (C=3)

$C_{net}=9$

Thus their net capacitance if connected in parallel is 9uf