Net force on the charge at origin is
(1) 5.5 x 10-3 N
(2) 4.6 x 10-3 N
(3) 2.2 x 10-2 N
(4) 3.5 x 10-3 N
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Answered by
1
Answer:
2
Explanation:
kq^2/r^2
9×10^9×{(1/4+1/81)^1/2}×10^-6
Answered by
1
Force along OA
F = K (2x10^-6)(1x10^-6)/4
9x10^9x10^-12/4
(9x10^-3)/4 j
force along OB
F= K (10^-12)/9
9x10^9x10^-12/9
10^-3 i
net force = √(81x10^-6)/16+10^-6
√97x10^-3/4
approx 2.5x10^-3
(3)
hope it helps u
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