Physics, asked by the63hvdB, 11 months ago


Net force on the charge at origin is
(1) 5.5 x 10-3 N
(2) 4.6 x 10-3 N
(3) 2.2 x 10-2 N
(4) 3.5 x 10-3 N​

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Answers

Answered by HarshilKankane
1

Answer:

2

Explanation:

kq^2/r^2

9×10^9×{(1/4+1/81)^1/2}×10^-6

Answered by pranjaygupta
1

Force along OA

F = K (2x10^-6)(1x10^-6)/4

9x10^9x10^-12/4

(9x10^-3)/4 j

force along OB

F= K (10^-12)/9

9x10^9x10^-12/9

10^-3 i

net force = √(81x10^-6)/16+10^-6

√97x10^-3/4

approx 2.5x10^-3

(3)

hope it helps u

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