New And First Question :-
A) A father’s age is three times the age of his two sons. After 5 years, his age will be twice the sum of the ages of his sons. What is the age of the father?
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Given,
- Father age is three times age of his two sons.
- After 5 years father age will be twice of the sum of his sons's age .
To Find,
- The age of the father = ?
Solution,
⇒Let the father age be a
And , the age of his two sons be b
According to the First Condition :-
⇒ x = 3y...........1) Equation
According to the Second Condition :-
⇒ x + 5 = 2(y + 10)
⇒ x + 5 = 2y + 20
⇒ x - 2y = 20 - 5
⇒x - 2y = 15 .........2) Equation
From First equation the value of x put in Second Equation :-
⇒x - 2y = 15
⇒3y - 2y = 15
⇒y = 15
Now put the value of y in First Equation :-
⇒x = 3y
⇒x = 3(15)
⇒x = 45
Therefore ,
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