Math, asked by bhurasaleha, 9 months ago

Newton's law of gravitation states that every body in the universe attracts every other body with a force F that varies directly as the product of their masses (m1, m2) and inversely as the square of the distance d between them. If both masses are increased by 90% and the distance between them is halved, by what percent will the force of attraction increase? i want to know by what percent the force of attraction increase? this question is from edugen willey plus.

Answers

Answered by Anonymous
6

Answer:

See the attachment above...

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Answered by pulakmath007
2

Answer:

By the law

F = m1 ×m2 / d^2

If both masses are increased by 90% and the distance between them is halved

Then new force

= F' =( 190/100) m1 ×(190/100)m2 / (d/2)^2

= 14.44 m1 ×m2 / d^2 = 14. 44 F

So increment = F'-F= 14.44F - F = 13.44 F

So the required answer is

= 13.44 ×100%

=1344 %

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