(NH4)3PO4 contains 3.18 moles of H atom. Then number of moles of oxygen atom present
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Let's count individual atoms in [math](NH_4)_3PO_4[/math]
[math]\begin{align} N &= 3 \\ H &= 12 \\ P &= 1 \\ O &= 4 \end{align}[/math]
From this,we come to know that 12 moles of Hydrogen correspond to 3 moles of Oxygen.
Let [math]x[/math] moles of Oxygen correspond to 3.18 moles of Hydrogen
[math]\begin{align} \therefore \dfrac{x}{4} &= \dfrac{3.18}{12} \\ \therefore x &= \dfrac{3.18×4}{12} \\ &= \dfrac{3.18}{3} \\ &= \boxed{\boxed{1.06 moles}} \end{align}[/math]
Therefore, 1.06 moles of Oxygen is present in the sample.
hope it help you
[math]\begin{align} N &= 3 \\ H &= 12 \\ P &= 1 \\ O &= 4 \end{align}[/math]
From this,we come to know that 12 moles of Hydrogen correspond to 3 moles of Oxygen.
Let [math]x[/math] moles of Oxygen correspond to 3.18 moles of Hydrogen
[math]\begin{align} \therefore \dfrac{x}{4} &= \dfrac{3.18}{12} \\ \therefore x &= \dfrac{3.18×4}{12} \\ &= \dfrac{3.18}{3} \\ &= \boxed{\boxed{1.06 moles}} \end{align}[/math]
Therefore, 1.06 moles of Oxygen is present in the sample.
hope it help you
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