Question

ni(cl)4 2- shap of complex​

Answer 1

Answer:

tetrahedral structure .

Answer 2

Explanation:

$\mathsf{[NiCl_{4}] {}^{2 - } }$

Calculation of O.N. -

x - 1×4 = -2

x = -2 + 4

x = 2

Electronic configuration of Ni

$\mathsf{[Ar] 4s {}^{2} 3d {}^{8} }$

$\mathsf{Electronic \: configuration \: of \: Ni {}^{2 + } }$

$\mathsf{[Ar] 3d {}^{8} }$

Orbital diagram :-

( Refer to the attachment. )

Calculation of C.N. -

→ 1×4

→ 4

Hence,

Hybridisation = sp³

Shape = Tetrahedral