nia weighs 4 kg less than maggie who weighs 3 kg less than pedro . Altogether they weigh 137 kg . Of maggie weighs x kg what is the weight of each of pedro and nia in terms of x
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Age of maggie= X
Then age of Nia=X-4
Age of Pedro=x+3
Sum of their weights=137 Kg
X+(X-4)+(X+3)= 137
X+X-4+X+3= 137
3X-1=137
3X= 137-1
3X=136
X=136/3
X=46(nearly)
Age of Maggie(X)=46
Age of Nia (X-4)=46-4=42
Age of Pedro(X+3)=46+3=49
Then age of Nia=X-4
Age of Pedro=x+3
Sum of their weights=137 Kg
X+(X-4)+(X+3)= 137
X+X-4+X+3= 137
3X-1=137
3X= 137-1
3X=136
X=136/3
X=46(nearly)
Age of Maggie(X)=46
Age of Nia (X-4)=46-4=42
Age of Pedro(X+3)=46+3=49
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