Nick draws water from a well having depth of 5m. Calculate the maximum weight of water he can pull up if the maximum work he is capable of doing is 100 J and he is using a rope to lift the water which can bear a maximum load of 18N.
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Answer:Two ways to approach this problem:
The more complex method using calculus:
or
The simple way shown below
Work = (force)(distance)
If you are lifting a load, the force = weight = mg, and the distance = lifting height.
Work = (weight)(height)=(mg)h
An easy way to deal with the rope weight is to treat it as a concentrated load located at the center of gravity of the rope (i.e. at 25 m depth).
mrope=(0.2kgm)(50m)=10kg
So the total work done is:
(mgh)water+(mgh)rope=(20)(9.81)(50)+(10)(9.81)(25)
=12300Nm.
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