nickel and iron mixed in the ratio of 4:5 and 4:11 to make 2 allows namely x and y.
Answers
Answer:
Explanation:
16:29
Given : Nickel and iron are mixed in the ratio of 4:5 and 4:11 to make two alloys namely, X and Y, respectively.
third alloy, Z. by mixing equal quantities of X and Y.
To Find : What will be the ratio of nickel and iron present in the alloy Z?
Solution
Let say X and Y Quantity are 45A
Nickel and iron are mixed in the ratio of 4:5 in X
Hence Nickle in X = (4/(4 + 5))*45A = 20A
Iron in X = (5/(4 + 5))*45A = 25A
Nickel and iron are mixed in the ratio of 4:11 in Y
Hence Nickle in Y = (4/(4 + 11))*45A = 12A
Iron in Y = (11/(4 + 11))*45A = 33A
Total Nickle = 20A + 12A = 32A
Total Iron = 25A + 33A = 58A
Iron : Nickle = 32A : 58A
=>Iron : Nickle = 16 : 29
Ratio of iron to nickle in Z alloy is 16:29
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