Question

Nickel atom can lose two electrons to form Ni^2+ ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.

Answer 1

Explanation:

Atomic number of nickel is 28 and its electronic configuration is as follows.

      $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{8}$

In $Ni^{2+}$, there will be two electrons less than the number of electrons present in a neutral nickel atom.

Therefore, electronic configuration of $Ni^{2+}$ is as follows.

       $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{0}3d^{8}$

or,    $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8}$

Thus, we can conclude that nickel will lose two electrons from 4s orbital.