Question

Nickel( atomic mass= 58.7) has a FCC unit cell edge of 352pm. Calculate its density.​

Answer 1

Answer:

6.0287×10

23

Explanation:

a=352.39pm ρ=8.9g/cm

3

, M

A

=58.7, N

A

=? , Z=4 FCC

ρ=

N

A

×a

3

Z×M

A

8.9=

N

A

×43.76×10

−24

4×58.7

⇒N

A

=6.0287×10

23