Nickel crystallizes in a fcc unit cell with a cell edge length of 0.3524nm.calculate the radius of the nickel atom?
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Answer:
r=0.124nm
Explanation:
Z = 4[FCC]
a = 0.3524nm
r=?
hence in FCC
r=a÷2×root2
r=0.3524 ÷2.828
r=0.124nm
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