Question

Nidhi has 3 times as many rupees 2 coins as she has rupees 5 coins. If she has in all a sum of rupees 77 how many coins of each denomination does she have please answer me fast

Answer 1

let the number of 2 rupees coins be x and 5 rupees be y.
from 1st condition
$x = 3y \\ x - 3y = 0.......1$
from 2nd condition
$2x + 5y = 77.......2$
multiply 1 with -2
$- 2x + 6y = 0......3$
adding 2 and 3
we get
$11y = 77 \\ y = 7$
put y=7 in 1
$x - 7 \times 3 = 0 \\ x = 21$
Therefore there are 21 number of 2 rupees coin and 7 number of 5 rupees coin.
Hope this helps you:)))
don't forget to do it brainleist.

Answer 2

Nidhi has 3 times as many Rs. 2 coins as she has Rs. 5 coins. If she has in all a sum of Rs. 77

We need to find, how many coins of each denomination does she have?

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

⠀⠀⠀⠀⠀⠀⠀⠀⠀$\underline{\bigstar\:\boldsymbol{According\:to\: Question\::}}$

Nidhi has 3 times as many Rs. 2 coins as she has Rs. 5 coins. So,

☯ Let the number of Rs. 5 coins be x.

☯ Therefore, number of Rs. 2 coins will be 3x.

Given sum of both coins is 77.

Therefore,

$:\implies\sf 5 \times (x) + 2 \times (3x) = 77$

$:\implies\sf 5x + 6x = 77$

$:\implies\sf 11x = 77$

$:\implies\sf x = \cancel{ \dfrac{77}{11}}$

$:\implies{\boxed{\frak{\purple{x = 7}}}}\;\bigstar$

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Hence,

• Number of Rs. 5 coins, x = 7

• Number of Rs. 2 coins, 3x = 3 × 7 = 21

$\therefore\;{\underline{\sf{She\;have\;7\;coins\;of\;Rs.\;5\;and\;21\;coins\;of\;Rs.\;2.}}}$