Niharika walks thrice around a square field of side 22 m .Girish walks twice around a rectangular field with length 10 m and breadth 12m .who covers more distance and by how much?
Answers
Answered by
3
Answer: Niharika covers more distance by 176m.
Step-by-step explanation:
Total area covered by Niharika
= 3[4*22]m (perimeter of square is 4*side)
= 264m.
Total area covered by Girish
=2*2*(10+12)m
[perimeter of rectangle is 2*(length+breadth)]
=88m.
Excess of distance covered by Niharika
= (264-88)m
= 176m.
Step-by-step explanation:
Total area covered by Niharika
= 3[4*22]m (perimeter of square is 4*side)
= 264m.
Total area covered by Girish
=2*2*(10+12)m
[perimeter of rectangle is 2*(length+breadth)]
=88m.
Excess of distance covered by Niharika
= (264-88)m
= 176m.
adithisatheesh2155:
the answer is wrong
this one
you need to find the perimeter and not the area because the question is give as they walk 'around' the field n not walk 'inside' the field
I am also thinking that only
first u had written something else
what I have written
this one is correct
please give this one the brainliest answer
Answered by
3
Answer:
Niharika covered more distance by 176m.
Step-by-step explanation:
side of square = 22m
perimeter of square = 4 * 22 = 88m
total distance covered by Niharika = 3 * 88 = 264m
length of rectangular field = 10m
breadth of rectangular field = 12m
perimeter of rectangular field =2 ( 10 + 12 ) = 44m
total distance covered by Girish = 2 * 44 = 88m
Niharika covered more distance by 176 m { ∵264 - 88 = 176m }
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