Math, asked by KumarMishra110011, 1 month ago

Nimnlikhit samikaran Yug mein a^1/a^2, b^1/b^2 or c^1/c^2 ki tulna kijiye 6x-3y+10=0 2x-y+9=0

Answers

Answered by tv9sprasad
0

Here I didn't understood your question but I am assuming that it is a1/a2

Given,

6x-3y+10=0,2x-y+9=0

by comparing with ax+by+c=0

a1=6,b1=-3,c1=10

a2=2,b2=-1,c2=9

since,a1/a2=b1/b2 and not equal to c1/c2

the line are parallel

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