Nine grams of aluminium reacts with sixteen grams of X.Eight grams of X can react with how many grams of hydrogen(assuming valency of X is same in both the compounds
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Al : X = 9 : 16 ...... (i)
Al : H = 27 : 3 ..... (ii)
Multiply (i) by 3
Al : X = 27: 48
Al : H = 27: 3
⇒ X : H = 48 : 3 = 16 : 1
16g og X react with 1g of H
∴ 8g of X = (8 x 1)/16
= 0.5 g
Al : H = 27 : 3 ..... (ii)
Multiply (i) by 3
Al : X = 27: 48
Al : H = 27: 3
⇒ X : H = 48 : 3 = 16 : 1
16g og X react with 1g of H
∴ 8g of X = (8 x 1)/16
= 0.5 g
Answered by
4
Answer:
Explanation:
Al : X = 9 : 16 ...... (i)
Al : H = 27 : 3 ..... (ii)
Multiply (i) by 3
Al : X = 27: 48
Al : H = 27: 3
⇒ X : H = 48 : 3 = 16 : 1
16g og X react with 1g of H
∴ 8g of X = (8 x 1)/16
= 0.5 g
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