Question

Niobium forms BCC structure. The density of Niobeium is 8.55 genr The length of unit cell
edge is 330.6 pm. How many atoms and unit cells are present in 0 Sg niobium?
​

Answer 1

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N

0

) and edge length (a) are related as below:

D=

N

0

a

3

ZM

Given D=8.55 g/cm

3

and M=93 u.

Edge length =a=(

DN

0

ZM

)

1/3

=(

8.55×6.023×10

23

2×93

)

1/3

=3.306×10

−8

cm

Atomic radius =r=

4

3

a=

4

3

×3.306×10

−8

=1.432×10

−8

cm=14.32 nm

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