Question

Nitin's age was equal to square of some number last year and the following year it would be cube of a number. If again Nitin's age has to be equal to the cube of some number, then for how long he will have to wait?

A.10 years
B.38 years
C.39 years
D.64 years​

Answer 1

Answer:

option c the correct answer

Answer 2

Answer:

B

Step-by-step explanation:

Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.

Such numbers are 25 and 27.

Thus, Nitin is now 26 years old. Since the next perfect cube after 27 is 64,

so required time period =(64−26) years =38 years.