Question

nitrogen and hydrogen combine in the ratio of 14:3 by mass to from ammonia. calculate the mass of nitrogen remains unreacted if the reaction vessels contain 50gram of nitrogen and 9gram of hydrogen.

Answer 1

Hello Mate,


Ans: Atomic mass of 1-Nitrogen atom = 14 grams Atomic mass of 1- Hydrogen atom = 1 Nitrogen and hydrogen combine in the ratio 14: 3 by mass. Therefore one Nitrogen atom combines with three Hydrogen atoms and molecular weight of the compound formed is 17. Formula of the compound formed in the given ratio and calulated molecular weight is NH₃(ammonia). Following equation shows the formation of ammonia molecule from Nitrogen and Hydrogen. N₂ + 3H₂→2NH₃  


Hope this helps you

Answer 2

N2 + 3H2-----> 2NH3
Ratio=14:3
H2=9g
N2=xg(mass which reacts with H2)

Comparing the mass ratio-
14/3=x/9. (/ represents division)
x= 14/3*9
x=14*3
x= 42g

42g is the required mass for the reaction with 9g of H2.
But we have to calculate the mass left after reaction. So,
Leftover mass(yg)= Total mass of N2(50g) - Reactant mass(42g)
=> y = 50 - 42
=> y = 8g
So the mass of N2 left after the reaction is 8g.
Thanks:)