Question

Nitrogen gas of mass 28 is kept in a vessel at pressure 10 atm and temperature 57°C. Due to leakage of N2 gas its pressure falls to 5 atm and temperature to 27°C. The amount of N2 leaked out is

Answer 1

Answer:

Leaked Gas = 0.81 x 15.46 = 12.522 g

Explanation:

As we know that,

PV = nRT

Given data :

P1 = 10 atm

T1 = 57 degree Celsius = 57 + 273 = 330 K

P2 = 5 atm

T2 = 300 K

P1V = n1 R T1 - - - - - - 1

P2V = n2 R T2 - - - - - - - 2

By dividing eq 1 by 2

P1 / P2  = n1  x T1 / n2 x T2

10 / 5 = n1 / n2 x 330 / 300

2 x 300 / 330 = original mass / remaining mass

original mass = 1.81 remaining mass

leaked gas = 0.81 x remaining mass

Remaining mass = 28 / 1.81 = 15.46

Leaked Gas = 0.81 x 15.46 = 12.522 g