Two identical resistors each of resistance 10 ohm are connected (i) series (ii) parallel in turn to a battery of 6 v, Calculate the ratio of power consumed in the combination of resistors in the two cases.
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Answer:
for effective resistance when resistors are connected in series reff=r1+r2
Step-by-step explanation:
reff= (10+10)ohms
20ohms
effective resistance when connected in parallel=1/Reff = 1/r1 + 1/r2
1/10 +1/10= 2/10 =1/5
therefore
1/Reff = 1/5
reff =5ohms
ratio= 20/5 = 4/1
= 4:1
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