Math, asked by asaithambi8021, 6 months ago

NJ
DS
find range real function
f(x)=x/1+ x2​

Answers

Answered by viashah
1

Step-by-step explanation:

f(x) = x/1+x2

f = x/1-x +x2

L. C. M of x/1-x is 1

then,

subtract from x/1 -x/1 =0

so,

f =x2

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