no. 10 In a quadilateral
Attachments:
Answers
Answered by
1
Hey mate,
here is your answer,
let the constant in ratio be X.
Therefore,
angle A = 2x
angle B = 7x
angle C = 8x
angle D = 3x.
now, as we know,
according to angle sum property of a quadrilateral, the sum of all angles is 360°..
Therefore,
angle (A+ B+ C+D) =360°
2x +3x+7x+8x =360°
20x=360°
x=18°
therefore,
angle a = 2×18 = 36°
angle b= 7×18= 126°
angle c= 8×18= 144°
angle d= 3×18° = 54°
hope it helps...
Please mark me as brianliest....
here is your answer,
let the constant in ratio be X.
Therefore,
angle A = 2x
angle B = 7x
angle C = 8x
angle D = 3x.
now, as we know,
according to angle sum property of a quadrilateral, the sum of all angles is 360°..
Therefore,
angle (A+ B+ C+D) =360°
2x +3x+7x+8x =360°
20x=360°
x=18°
therefore,
angle a = 2×18 = 36°
angle b= 7×18= 126°
angle c= 8×18= 144°
angle d= 3×18° = 54°
hope it helps...
Please mark me as brianliest....
tannu355838:
ok
Similar questions