Question

No 3,4,5 pl solve it

Answer 1

3)the gp serious is 1,-1/2,1/4,-1/8.......

let a first term and r be common ratio...

a=1 , r=-1/2/1=-1/2

now, we find 9 term so that

t9={ar}^{n-1}

=(1)(-1/2)^{8}

=1×{1/2}^{8}

=1/256 answer

all question same

Answer 2

Step-by-step explanation:

Hope it will help you...