Question

no 3 slove if you are really god of math

Answer 1

Length of an arc = 2 × π × radius × theta / 360

= π × r × theta / 180

Answer 2

area of circle= πr^2

616 = 22\7 r^2

616 ×7 \22 = r^2

56 ×7 \2= r^2

48× 7= r^2

196= r^2

13=r

Given ABC is an equilateral triangle and AD = h be the altitude. Hence these bisectors are also the altitudes and medians whose point of intersection divides the medians in the ratio 2 : 1 ∠ADB = 90° and OD = (1/3) AD That is r = (h/3) Þ h = 3r = 3 × 13 = 39 cm

Let each side of the triangle be a, then Altitude of an equilateral triangle is (√3/2) times its side

That is h = (√3a/2)

39=(√3a\2)

∴ a = 26√3 cm

We know that perimeter of an equilateral triangle = 3a = 3 × 26 √3

= 78√3

= 78× 1.73

= 45.0332cm