Question

no.4...plz do it with proper steps..​

Answer 1

The answer is option d

Answer 2

$\huge\boxed {Answer}$

polynomial is -

2x⁴ + 9x³ + 11x² + 4x - 6

When x = 1

then remainder is ,

2(1)⁴ + 9(1)³ + 11(1)² + 4(1) - 6

= 2 + 9 + 11 + 4 - 6

= 20

So , 1 is not the zero of above polynomial .

When x = -1

then remainder -

2(-1)⁴ + 9(-1)³ + 11(-1)² + 4(-1) - 6

= 2 - 9 + 11 - 4 - 6

= -6

-1 is also not the zero of above polynomial

When x = 3

then remainder -

2(3)⁴ + 9(3)³ + 11(3)² + 4(3) - 6

= is not equal to 0

Now ,

At x = -3

2(-3)⁴ + 9(-3)³ + 11(-3)² + 4(-3) - 6

= 2(81) + 9(-27) + 11(9) - 12 - 6

= 162 - 243 + 99 - 18

= 261 - 261

= 0

So , -3 is the zero of above polynomial .