Question

NO EXPLANATION NEEDED JUST THE RIGHT ANSWER

Water fills a spherical tank of diameter 16 meters until the water is 4 meters deep at the lowest point in the tank. What is the diameter of the surface of the water?

Answer 1

Diameter of surface of water is 4√3 m

Step-by-step explanation:

$\text{Diameter of tank = 16 m(given)}\\\text{ So radius of tank (c) = }\frac{Diameter}{2} = \frac{16}{2}\text{ =8 m}\\\\\text{Water reached 4 m deep, }\\\\\\\text{It means distance between center of tank and surface of water = a=8 - 4 = 4 m}\\\\\textbf{This is making a right angle triangle}$$\textbf{PYTHAGORUS THEOREM =} a^{2} + b^{2} = c^{2}$

$\text{Putting values of a and c}\\\\4^2 + b^2 = 8^2\\\\b^2= 8^2 - 4^2\\\\b^2 = 64 - 16 = 48\\\\\textbf{So}\\\\b=\sqrt{48} \\\\b=4\sqrt{3}$$\textbf{So the radius of water surface = }4\sqrt{3}\\\\\\\textbf{Then the diameter of the surface of water =} 2\times4\sqrt{3} \\\\\textbf{So the Diameter of the surface of water = }8\sqrt{3}$