Question

no fake answers.....plz​

Answer 1

Answer:

45 millilitres

Explanation:

Given that,

$P_{1}$ = 1×10^{5} Pa = 1 Bar

$P_{2}$ = 2×10^{5} Pa = 2 Bar

$V_{1}$ = 100cm^{3} = 0.1 Litres

$V_{2}$ = ?

$T_{1}$ = 313K

$T_{2}$ = 283K

By using combined Gas law,

i.e \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}

V_{2} = \frac{283}{10*313*2}

⇒V_{2} = 0.0452 litres

⇒ V_{2} = 45 millilitres

[HENCE, PROVED]

Answer 2

Answer:

45 millilitres

Explanation:

Given that,

P1= 1×10^{5} Pa = 1 Bar

P2 = 2×10^{5} Pa = 2 Bar

V 1= 100cm^{3} = 0.1 Litres

V 2= ?

T1 = 313K

T2 = 283K

By using combined Gas law,

i.e \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}

V_{2} = \frac{283}{10*313*2}

⇒V_{2} = 0.0452 litres

⇒ V_{2} = 45 millilitres

[HENCE, PROVED]