Question

no of atom in 4.25g of nh3 is approx

Answer 1

4.25/17*6.023*10power23

Answer 2

Hii..
Moles of 4.25g NH3 = 4.25÷17(weight÷molar mass of NH3)
=0.25 moles

Hence number of atoms in one mole=6.02×10²³

Therefore in 0.25moles
No. of atoms= 0.25 ×6.02×10²³
=1.5×10²³atoms..

Hence number of atoms in 4.25gm of NH3 are
1.5×10²³..

hope this helps!