no. of atoms in 16g of methane
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Answered by
0
molecular formula of methane = CH4
we know,
atomic mass of C = 12 g/mol
atomic mass of H = 1 g/mol
so,
molecular mass of CH4 =( 12 + 4 × 1 ) g/mol = 16 g/mol
also we know,
no of molecule = {given weight /molecular weight } × 6.023 × 10²³
here,
given weight = 16 g
molecular weight = 16 g/mol
so,
no of molecules = ( 16/16) × 6.023 × 10²³
= 6.023 × 10²³
we know,
atomic mass of C = 12 g/mol
atomic mass of H = 1 g/mol
so,
molecular mass of CH4 =( 12 + 4 × 1 ) g/mol = 16 g/mol
also we know,
no of molecule = {given weight /molecular weight } × 6.023 × 10²³
here,
given weight = 16 g
molecular weight = 16 g/mol
so,
no of molecules = ( 16/16) × 6.023 × 10²³
= 6.023 × 10²³
Answered by
1
No of molecules = wt/gmw *avagadro no
6.023*10^23
6.023*10^23
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