no of atoms in 22g of co2
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relative molevular mass of co2 is 44.(O=16,C=12).so the number of atoms in 44g is 6.022×10^23(avegadro constant).therefore the number of carbon atoms in 22g is6.022×10^23/2.as in one atom there is only one atom of carbon
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relative molevular mass of co2 is 44.(O=16,C=12).so the number of atoms in 44g is 6.022×10^23(avegadro constant).therefore the number of carbon atoms in 22g is6.022×10^23/2.as in one atom there is only one atom of carbon
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Answer:
3.011 * 10^23
Explanation:
moles of co2= given mass/moler mass of co2
moles of co2= 22/ 12 + 16(2)
moles of co2 =0.5
no. of atom of co2= no. of mole * avegdros constant
=0.5* 6.022 *10^23
=3.011 * 10^23
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