Question

no of atoms present in 0.1 mol of oxygen​

Answer 1

Answer:

6.02214199×10^23 is the exact answer for that given question .

Answer 2

Explanation:

no of atoms =

$\frac{1}{10} \times 6.022 { \times {10}^{23} }$

therfore

no.of atoms = 6.022 × 10^22

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