Question

No of atoms present in 5.6litre of CO2

Answer 1

1 mole of co2 (i.e 44g)occupies 22.4 I

x mole occupies 5.6I

.·. x = (44 * 5.6)/22.4

=11mol

Answer 2

Explanation:

1 mole of C02 =5.6L OF VOLUME

6.023×10^23 CARBON ATOMS =22.4L OF CO2

X ATOMS= 5.6 L

NOW BY CRISS CROSS METHOD

22.4 *X = 6.023 *10^23 * 5.6

X =6.023 ×10^23 *5.6/22.4

X=6.023×10^23/4

X= 1.5×10^23 ATOMS....

HOPE THIS HELPED YOU

GOOD LUCK...