no of electron in 5. c charge
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Answered by
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we know that
Q=ne (quantization charge)
n=Q/e
here Q=5c
e=1.6×10^-19c
we have to find that the value of n
so n=Q/e
n=5/1.6×10^-19
=5×10^20/16
=31.25×10^18
it is your answer. .....
Q=ne (quantization charge)
n=Q/e
here Q=5c
e=1.6×10^-19c
we have to find that the value of n
so n=Q/e
n=5/1.6×10^-19
=5×10^20/16
=31.25×10^18
it is your answer. .....
silu12:
thnx vimal
Answered by
0
Q=-+ne
here Q =5c
e=1.6×10^-19
n=?
then n=Q/e
5/1.6×10^-19
3.13000000E
hope this helps you
you can also write it as 3.13
here Q =5c
e=1.6×10^-19
n=?
then n=Q/e
5/1.6×10^-19
3.13000000E
hope this helps you
you can also write it as 3.13
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