Question

no. of gram atom present in 288g of sulphur

Answer 1

Answer:9 gram atom

1 gram atom consists of 32 g

So in 288g

Number of gram atom is 288/32

Which is equal to 9

Answer 2

The Number Of Gram Atoms In 288 Grams Of Sulfur Is 5.41 × 10²²

GIVEN

Weight of sulfur = 288 grams

TO FIND

The total number of gram atoms in the given weight of sulfur.

SOLUTION

We can simply solve the above problem as follows-

Gram atoms of a substance = Avogadro's number = Number of Moles of the given substance.

So, to calculate the number of gram atoms we need to find out the moles in 288 grams of sulfur

$number \: of \: moles = \frac{given \: mass}{molar \: mass}$

$= \frac{288}{32}$

$= 9 \: gm/mol$

We know that,

1 mole of sulfur = 6.022 × 10²³ atoms

9 moles of sulfur = 6.022 × 10²³ × 9

= 5.41 × 10²²

Hence, the Number of gram atoms in 288 grams of sulfur is 5.41 × 10²²

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