No.of lone pairs of electrons in 9gms of water are (N=Avagadro number)....???
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The Lewis structure for water is comprised of a polar covalent bond with 2 lone pairs (situated on the oxygen atom).
n (moles) =m(mass)/M(molar mass)
M of water: 18.015 g*mol^-1
m, obviously, is as given: 9 grams;
Therefore,
n=9grams/18.015g*mol^-1 = 0.5 mol (H2O)
Total number of lone pairs is then: 0.5*2*6.0221*10e+23 = 6.0221*10^23 lone
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n (moles) =m(mass)/M(molar mass)
M of water: 18.015 g*mol^-1
m, obviously, is as given: 9 grams;
Therefore,
n=9grams/18.015g*mol^-1 = 0.5 mol (H2O)
Total number of lone pairs is then: 0.5*2*6.0221*10e+23 = 6.0221*10^23 lone
plz mark as brainlist
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