Question

no.of.molecule in 4.25 g of NH 3 ​

Answer 1

hey mate,

We have,

n = w/M

where,

n = no. of moles

w = weight of the substance

M = molar mass.

Solution:

the molar mass of ammonia is 17 g/mol.

then,

n = 4.25/17

=0.25 moles.

now,

no. of molecule = no. of moles * Avogadro number.

m = 0.25 * 6.022 *10^23

= 1.505 *10^23. molecule.

is the answer .

hope it helps.

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