Question

no of molecules in 34.2 gm of h2o?

Answer 1

1 mole of C12H22O11=342gC12H22O11=342g

= 12 x 12 + 22 x 1 + 11 x 16 = 342 amu

=6.022×1023=6.022×1023 molecules

Now 342 g of cane sugar contain 6.022×10236.022×1023 molecules.

34.2 g of cane sugar will contain

=6.022×1022=6.022×1022 molecules

Answer 2

No.moles = Weight/ molecular weight

                =34.2/33

                =1.06 moles

1 mole-----> avagadro number of molecule (6.023×10²³)

1.06 moles--> 6.023×10²³×1.06= 6.24 molecule

Hope you Understand :)