Question

NO OF MOLECULES PRESENT IN 8g OF KNO3

Answer 1

Lets find out

Firstly determine the molar mass of potassium nitrate[KNO3]

39.1 + 14 + 3(16) = 101.10

Then simply divide mass/molar mass of KNO3

Mass of KNO3 = 8g

Molar mass of KNO3 = 101.10

No. of molecules = 0.079

0.079 moles are present in 8g of KNO3

Answer 2

We have to determine the number of molecules present in 8g of potassium nitrate

Now we have KNO3 . This is known as potassium nitrate.

The elements are potassium, nitrogen and oxygen. Here there are three parts of oxygen and others are one part.

The mass of the elements are

39.1 + 14 + 16(3) = 39.1 + 14 + 48 = 101.1

After adding all the elements we get 101.1

Therefore  

101.1 g of potassium nitrate is present in 1 mole

8 g is present in  8/101.1 moles

SO we get 0.079 molecules is present in 8 g of potassium nitrate.