No.of N2 molecules present in 1 L vessel at NTP when compressibility factor is 1 .2 is -
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Answered by
0
PV = Z n RT
as P= 1 atm, V= 1L, T = 298 kelvin ,Z= 1.2
as 1/ RT = 12
then n= 1/RT × 1/ 1.2=12/1.2= 10 ans. i hope it may help u
Shanaya0516:
But ans. is 2 23× 10 ^ 22
hmm
what hmmm
make it correct
edit ur answe
i did wt i could now try urself and put the exact values of R-T
Answered by
23
PV = ZnRT
P= 1 atm, V=1L, Z= 1.2, R= 0.082, T=273K
1.2 x 273 x 0.082(n)= 1
n= 1/26.86
n= 0.037
Now number of molecules
= 0.037 x 6.022x10^23
= 0.223x 10^23
=2.23x 10^22
P= 1 atm, V=1L, Z= 1.2, R= 0.082, T=273K
1.2 x 273 x 0.082(n)= 1
n= 1/26.86
n= 0.037
Now number of molecules
= 0.037 x 6.022x10^23
= 0.223x 10^23
=2.23x 10^22
Tu
Ty
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