No. of nh₄ ions in 74.5g of (nh₄)₃po₄
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6.385714×10^22
Explanation:
for 112g it is 6.023×10^23 atoms so for 74.5g it is 4.006×10^23 atoms.
no of NH4 ions in 112 g is 9.6×10^22 then in 74.5 it is given above in answer.
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