Chemistry, asked by indrajadhavrao3377, 11 months ago

No. of nh₄ ions in 74.5g of (nh₄)₃po₄

Answers

Answered by rakshitadr13
0

6.385714×10^22

Explanation:

for 112g it is 6.023×10^23 atoms so for 74.5g it is 4.006×10^23 atoms.

no of NH4 ions in 112 g is 9.6×10^22 then in 74.5 it is given above in answer.

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