Question

No.of protons present in 32g of SO2

Answer 1

Answer:

Moles = GIVEN WEIGHT / MOLECULAR MASS

32/64 = 1/2 MOLES

PROTONS = 16+8+8 = 32

TOTAL NUMBER OF PROTONS = 1/2×6.022×10^23× 32

= 3.011×10^23 ×32

=96.352 ×10^23

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Answer 2

Concept:

The number of moles can be defined as the ratio of a given mass to the molecular mass.

Given:

A sample of 32 g of SO₂.

Find:

The total number of protons present.

Solution:

The molecular mass of  SO₂,

SO₂ = 32 + 2(16) = 64 g/mol

n = (32 g) / (64 g/mol)

n = 0.5 mole

Number of atoms present in the sample,

N = nA

N = (0.5 moles) (6.022 × 10²³ molecules/mole)

N = 3.011 × 10²³ molecules

In Sulphur, the number of protons is 16, as the atomic number is 16 and In Oxygen, the number of protons is 8, as the atomic number is 8, but there are 2 moles of oxygen. So, the total number of protons is 32.

Total number of protons,

N = 32 × 3.011 × 10²³ protons

N = 9.6352  × 10²⁴ protons

Hence, the total number of protons present in 32g of SO₂ is 9.6352  × 10²⁴ protons.

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