Question

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Answer 1

Answer:

Its the 3rd option.

As lets take ã as angular acceleration

Torque = ã × Moment of inertia

ã = T/ I

ã = 2 F R ÷ M R*2 / 2

ã = 4F/ MR

As Torque is F× R

And moment of ineria of disc is MR*2 /2

Answer 2

Question :-

Two equal and opposite forces are applied tangentially to a uniform disc of mass M and radius R as shown in figure .if the disc is pivoted at its centre and free to rotate in this plane, the angular acceleration of the disc is .. ?

Answer :-

Two forces applied on the disc but the direction is opposite ..

we get it ..

T ( torque) = 2FR

we applied moment of inertia on the solid and regular body (disc)

we get it ..

T(torque) = MR^2 × alpha / 2

alpha = angular acceleration.

for the solution see the adjoining attachment...

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