Question

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Answer 1

✔✔Here is your answer in the attachment ✔✔

Answer 2

SOLUTION♥️

Velocity of wave in stretched string is given by,

$= > v = \sqrt{ \frac{t}{m} }$

where,

T is the tension

m is the mass /length.

If l is the length of the string then time taken by wave to reach the other end of string is,

$t = \frac{e}{v} = l \sqrt{ \frac{m}{t} }$

Given,

l= 20m

T= 200N

$= > \frac{m}{l} = \frac{2.5}{20} \\ = > \frac{1}{8} kg \:per \: meter$

Therefore,

Time taken to reach the other end of the string is

$= time= l \sqrt{ \frac{m}{t} } \\ \\ = > 20 \sqrt{ \frac{1}{8 \times 200} } = 0.5 \: seconds$

HOPE it helps ✔️☺️