Question

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Answer 1

Step-by-step explanation:

$\huge\underline\mathfrak\color{red} Answer$

a] part...

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〰Given that :- 4√2

〰To prove :- 4√2 is an irrational number .

⚫We shall prove this by the method of Contraction . so let us assume that 4√2 is a Rational Number .

4√2 = r

√2 = r/4

Now, we know √2 is an irrational number.

So RHS { r/4 } cannot be rational . As then the equation will be false .

So our Assumption is Wrong .

Hence , 4√2 is an irrational number .

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b] part.....

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Let us assume that 3 + √5 is a rational number.

Now,

3 + √5 = (a ÷ b)

[Here a and b are co-prime numbers]

√5 = [(a ÷ b) - 3]

√5 = [(a - 3b) ÷ b]

Here, {(a - 3b) ÷ b} is a rational number.

But we know that √5 is a irrational number.

So, {(a - 3b) ÷ b} is also a irrational number.

So, our assumption is wrong.

3 + √5 is a irrational number.

Hence, proved.

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hope it helps you sindhu;!

hope it helps you sindhu;!plz Mark as brainliest answer!;)

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Answer 2

hi sindhu ......how are you ....

stay safe ....and be happy ...

ur answer is attached above ....

have a nice day ....