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10y + x
reversing the digits = 10x + y
(10y + x) = (10x + y) + 27 ⇒ 10y + x – 10x – y = 27 ⇒ 9y – 9x – 27=0 ∴ x – y + 3 = 0
Thus the required linear equation is x – y + 3 = 0
reversing the digits = 10x + y
(10y + x) = (10x + y) + 27 ⇒ 10y + x – 10x – y = 27 ⇒ 9y – 9x – 27=0 ∴ x – y + 3 = 0
Thus the required linear equation is x – y + 3 = 0
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heya here is ur answer.....
hope helpful.....
hope helpful.....
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