Question

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The temperature at which the kinetic energy of gas molecules becomes double as compared to its value at 27°C is .....?

Answer 1

Kinetic energy = n/2 KT where n is degree of freedom
like kinetic energy = 3/2 KT
for mono atomic gas
for diatomic it's 5/2 KT
As kinetic energy is directly proportional to temperature
so doubling the kE would double the temperature

SO at temp.(27 degree celsius) it's 27×2 = 54 degree celsius or (54+273) kelvin = 327kelvin,kinetic energy would be double

Answer 2

Here your answer goes

Thanks for asking this Question !

Step :- 1

We know that ,

0°Celsius = 273 Kelvin

Step :- 2

According to Question add 27°C to 273

273 + 27 Should be equal to 300 Kelvin

Step :- 3

Given ,

The temperature at which the kinetic Energy of gas molecules becomes Double as Compare to it's value at 27°C

So , Simply  it means to double the energy

Step :- 4

For that We need to add 300 Kelvin or Celsius

300 + 300 = 600 Kelvin

Or We can say that 327 Celsius as We have already studied in our previous Classes that for Converting Kelvin into Celsius We have to Subtract 273 from the given value of kelvin

It Should be like that ,

600 ( Given  Value of Kelvin ) - 273

It Becomes 327 Celsius

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