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A Ball of mass 100 g moving with a velocity of 10m/s is stopped by a boy in 0.4 seconds. Calculate the force applied by the boy to stopped the ball.

Answer 1

Answer :-


Given

mass = 100g

initial velocity = 0 m/sec

final velocity = 10 m/sec

Time = 0.4 sec

Force = ?

we calculate first of all acceleration

V = u + at

10 = 0 + 0.4a

0.4a = 10

a = 10/0.4

a = 25 m/sec^2

mass = 100g it's convert into kg = 100/1000 = 0.1 kg

now,

F = mass * acceleration

= 0.1 * 25

= 1 * 25 /10

= 2.5 Newton

______________________________

Answer 2

mass=100g
initial velocity as provided = 0m/s
final velocity =10 m/s
time as provided = 0.4 seconds
force = ? ( mass . acceleration )
first calculate the asseleration=>
10= 0+0.4a
a=25 m/s^2
mass=0.1 kg
0.1 ×25=

2.5 newtons

hope so it will help u

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