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GIVEN a,b,c,d are FOUR REAL NUMBERS such that |a- b| =2 ,
|b - c| = 3 , |c - d| = 4 . Then Find the value of |a - d|.
✖️remember answer is not 9 ✖️
Answers
Answered by
8
Answer:
16
Step-by-step explanation:
(1+a)(1+b)(1+c)(1+d)
= (1 + ab + a + b)(1 + cd + c + d)
= 1 + cd + c + d + ab + abcd + abc + abd + a + acd + ac + ad + b + bcd + bc + bd
= 1 + abcd + a + b + c + d + ab + ac + bc + bd + ad + cd + abc + abd + acd + bcd
abcd = 1
so,,
abc + d ≥2 , abd + c ≥2 , bcd + a ≥2 , acd + b ≥2
≥ 1 + 1 + 2 + 2 + 2 + 2 + ab + ac + bc + bd + ad + cd
abcd = 1
so ab + cd ≥ 2 , ac + bd ≥ 2 , ad + bc
≥ 2
≥ 10 + 2 +2 + 2
≥ 16
So 16 is the right answer
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Verification
let say a , b , c , d all are = 1
abcd = 1
(1+a)(1+b)(1+c)(1+d) = 2 * 2* 2* 2 = 16
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