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5th and 6th question
Answers
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heya your ans
Q6. ans
First of all let assume mas of chain hanging down is "m" while it's length is "l".
Total length of chain "L" while total mass is "M".
So from the given data we know that M is equal to 4kg
total length=L=2m
l = 60 cm = 0.6 m As we know that 1 meter=100cm
Thus we know that
m= I/L * M
m=(0.6/2 )* 4= 1.2kg
In order to find out the tension of strain the formula is =mg
=1.2*10 = 12 Newton
we know that the tension is equal to force required and 0.6 is actually the displacement because that part is hanging
So also we know
work done= force*displacement
now as we have readings so just put the value
Work done = 12 * 0.6 = 7.2 J
So the work done in this case will be equal to 7.2 J.
and 5 ans
Given
F= 5i-3j+2k
now, distance(x) =r2-r1
X= (5i+2j+8k)-(2i+7j+4k)
=3i-5j+4k
Again,
W= F.X
= (5i-3j+2k).(3i-5j+4k)
= 38 joule
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Answer is 38 joule dearrrrrrr